If it's not what You are looking for type in the equation solver your own equation and let us solve it.
16t^2-28t-8=0
a = 16; b = -28; c = -8;
Δ = b2-4ac
Δ = -282-4·16·(-8)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-36}{2*16}=\frac{-8}{32} =-1/4 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+36}{2*16}=\frac{64}{32} =2 $
| 4+5y=78 | | 7/8=w/100 | | 5/8=w/100 | | d/10-2/6=11/30 | | 7x=24,5 | | 2x^2-2×-7=0 | | 5x-3÷4=2x+3 | | 3^(x+1)−29=−18∗3^(−x) | | 1560*v=1000 | | x-1=1/2× | | 2/5(n)=32 | | 7×x=x-12 | | 25/n=32 | | t/15=12 | | t/15=4 | | 3^x=0,2 | | x=(x+1)(x+3)(x+5)-x(x+3)(x+5) | | 5(x+x+1+x+2)=150 | | 7x+3=2(4x-1) | | x=1/8+1/6+1/3=9 | | 27+x/3=15 | | 0.6x=7x | | 5x³=15x⁴ | | 5x³=+15x⁴ | | 5x³+15=x⁴ | | 6x–10=–2x+30 | | 122=2w+2(wX35) | | 122=2w+2(w.35) | | {3}^{2x}-9{3}^{x}+18=0 | | 9x/7=9 | | 5(f=2)=9+5f | | 5x-(2-x)=3(x+4) |